तीन समुच्चयों के लिए (n(A)=48), (n(B)=50), (n(C)=44), (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16) और (n\(A\cap B\cap C\)=7) है। (n\(A\cup B\cup C\)) कितना होगा?
For three sets (n(A)=48), (n(B)=50), (n(C)=44), (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16) and (n\(A\cap B\cap C\)=7). What is (n\(A\cup B\cup C\))?
Explanation opens after your attempt
A. (95)
Concept
By the formula, (48+50+44-20-18-16+7=95). In three sets, the common triple part must be added back.
Why this answer is correct
The correct answer is A. (95). By the formula, (48+50+44-20-18-16+7=95). In three sets, the common triple part must be added back.
Exam Tip
सूत्र से (48+50+44-20-18-16+7=95) मिलता है। तीन समुच्चयों में अंतिम साझा भाग को वापस जोड़ना जरूरी है।
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