रेखाओं (y=3x+2) और (y=3x-4) के लिए असमानताओं \(y\leq 3x+2\) और \(y\geq 3x-4\) का हल-क्षेत्र क्या होगा?

For the lines (y=3x+2) and (y=3x-4), what is the solution region of \(y\leq 3x+2\) and \(y\geq 3x-4\)?

Explanation opens after your attempt
Correct Answer

A. दोनों समानांतर रेखाओं के बीच की बंद पट्टीClosed strip between the two parallel lines

Step 1

Concept

The condition is \(3x-4\leq y\leq 3x+2\). Since equality is allowed, both boundary lines are included.

Step 2

Why this answer is correct

The correct answer is A. दोनों समानांतर रेखाओं के बीच की बंद पट्टी / Closed strip between the two parallel lines. The condition is \(3x-4\leq y\leq 3x+2\). Since equality is allowed, both boundary lines are included.

Step 3

Exam Tip

शर्त \(3x-4\leq y\leq 3x+2\) है। बराबरी होने से दोनों सीमा रेखाएं शामिल होंगी।

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Mathematics Answer, Explanation and Revision Hints

रेखाओं (y=3x+2) और (y=3x-4) के लिए असमानताओं \(y\leq 3x+2\) और \(y\geq 3x-4\) का हल-क्षेत्र क्या होगा? / For the lines (y=3x+2) and (y=3x-4), what is the solution region of \(y\leq 3x+2\) and \(y\geq 3x-4\)?

Correct Answer: A. दोनों समानांतर रेखाओं के बीच की बंद पट्टी / Closed strip between the two parallel lines. Explanation: शर्त \(3x-4\leq y\leq 3x+2\) है। बराबरी होने से दोनों सीमा रेखाएं शामिल होंगी। / The condition is \(3x-4\leq y\leq 3x+2\). Since equality is allowed, both boundary lines are included.

Which concept should I revise for this Mathematics MCQ?

The condition is \(3x-4\leq y\leq 3x+2\). Since equality is allowed, both boundary lines are included.

What exam hint can help solve this Mathematics question?

शर्त \(3x-4\leq y\leq 3x+2\) है। बराबरी होने से दोनों सीमा रेखाएं शामिल होंगी।