फलन (f(x)=\frac{x+1}{x-2-9}) का प्रांत ज्ञात कीजिए।

Find the domain of (f(x)=\frac{x+1}{x-2-9}).

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-3,3}\)

Step 1

Concept

The denominator must satisfy \(x^2-9\ne 0\), so \(x\ne -3,3\). In exams, remove values that make the denominator zero.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-3,3}\). The denominator must satisfy \(x^2-9\ne 0\), so \(x\ne -3,3\). In exams, remove values that make the denominator zero.

Step 3

Exam Tip

हर \(x^2-9\ne 0\) होना चाहिए, इसलिए \(x\ne -3,3\)। परीक्षा में हर को शून्य बनाने वाले मान हटाएं।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{x+1}{x-2-9}) का प्रांत ज्ञात कीजिए। / Find the domain of (f(x)=\frac{x+1}{x-2-9}).

Correct Answer: A. \(\mathbb{R}-{-3,3}\). Explanation: हर \(x^2-9\ne 0\) होना चाहिए, इसलिए \(x\ne -3,3\)। परीक्षा में हर को शून्य बनाने वाले मान हटाएं। / The denominator must satisfy \(x^2-9\ne 0\), so \(x\ne -3,3\). In exams, remove values that make the denominator zero.

Which concept should I revise for this Mathematics MCQ?

The denominator must satisfy \(x^2-9\ne 0\), so \(x\ne -3,3\). In exams, remove values that make the denominator zero.

What exam hint can help solve this Mathematics question?

हर \(x^2-9\ne 0\) होना चाहिए, इसलिए \(x\ne -3,3\)। परीक्षा में हर को शून्य बनाने वाले मान हटाएं।