फलन (f(x)=\frac{\sqrt{x-3}}{\sqrt{7-x}}) का प्रांत चुनिए।

Choose the domain of (f(x)=\frac{\sqrt{x-3}}{\sqrt{7-x}}).

Explanation opens after your attempt
Correct Answer

A. ([3,7))

Step 1

Concept

For the numerator square root \(x-3\ge 0\), and for the denominator square root (7-x>0). Thus \(x\in[3,7\)).

Step 2

Why this answer is correct

The correct answer is A. ([3,7)). For the numerator square root \(x-3\ge 0\), and for the denominator square root (7-x>0). Thus \(x\in[3,7\)).

Step 3

Exam Tip

ऊपर के वर्गमूल के लिए \(x-3\ge 0\) और हर के वर्गमूल के लिए (7-x>0) चाहिए। अतः \(x\in[3,7\))।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{\sqrt{x-3}}{\sqrt{7-x}}) का प्रांत चुनिए। / Choose the domain of (f(x)=\frac{\sqrt{x-3}}{\sqrt{7-x}}).

Correct Answer: A. ([3,7)). Explanation: ऊपर के वर्गमूल के लिए \(x-3\ge 0\) और हर के वर्गमूल के लिए (7-x>0) चाहिए। अतः \(x\in[3,7\))। / For the numerator square root \(x-3\ge 0\), and for the denominator square root (7-x>0). Thus \(x\in[3,7\)).

Which concept should I revise for this Mathematics MCQ?

For the numerator square root \(x-3\ge 0\), and for the denominator square root (7-x>0). Thus \(x\in[3,7\)).

What exam hint can help solve this Mathematics question?

ऊपर के वर्गमूल के लिए \(x-3\ge 0\) और हर के वर्गमूल के लिए (7-x>0) चाहिए। अतः \(x\in[3,7\))।