फलन (f(x)=x-2-6x+8) का ग्राफ (x)-अक्ष को किन बिंदुओं पर काटता है?
At which points does the graph of (f(x)=x-2-6x+8) cut the (x)-axis?
Explanation opens after your attempt
A. ((2,0)) और ((4,0))((2,0)) and ((4,0))
Concept
Since (x-2-6x+8=(x-2)(x-4)), the zeroes are (x=2) and (x=4). In exams, set (y=0) for (x)-intercepts.
Why this answer is correct
The correct answer is A. ((2,0)) और ((4,0)) / ((2,0)) and ((4,0)). Since (x-2-6x+8=(x-2)(x-4)), the zeroes are (x=2) and (x=4). In exams, set (y=0) for (x)-intercepts.
Exam Tip
(x-2-6x+8=(x-2)(x-4)) इसलिए शून्य (x=2) और (x=4) हैं। परीक्षा में (x)-अवरोध के लिए (y=0) रखें।
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