पास्कल संबंध के अनुसार \(^{6}C_2\) किसके बराबर है?

According to Pascal's relation \(^{6}C_2\) is equal to what?

Explanation opens after your attempt
Correct Answer

D. \(^{5}C_2+^{5}C_1\)

Step 1

Concept

Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.

Step 2

Why this answer is correct

The correct answer is D. \(^{5}C_2+^{5}C_1\). Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.

Step 3

Exam Tip

सूत्र \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=6) और (r=2) रखें। परीक्षा में (n) दोनों पदों में (1) कम होता है।

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Mathematics Answer, Explanation and Revision Hints

पास्कल संबंध के अनुसार \(^{6}C_2\) किसके बराबर है? / According to Pascal's relation \(^{6}C_2\) is equal to what?

Correct Answer: D. \(^{5}C_2+^{5}C_1\). Explanation: सूत्र \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=6) और (r=2) रखें। परीक्षा में (n) दोनों पदों में (1) कम होता है। / Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.

Which concept should I revise for this Mathematics MCQ?

Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.

What exam hint can help solve this Mathematics question?

सूत्र \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=6) और (r=2) रखें। परीक्षा में (n) दोनों पदों में (1) कम होता है।