पास्कल संबंध के अनुसार \(^{6}C_2\) किसके बराबर है?
According to Pascal's relation \(^{6}C_2\) is equal to what?
Explanation opens after your attempt
D. \(^{5}C_2+^{5}C_1\)
Concept
Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.
Why this answer is correct
The correct answer is D. \(^{5}C_2+^{5}C_1\). Put (n=6) and (r=2) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams (n) decreases by (1) in both terms.
Exam Tip
सूत्र \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=6) और (r=2) रखें। परीक्षा में (n) दोनों पदों में (1) कम होता है।
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