(6) अलग-अलग अंकों से (6) अंकों की संख्याएं बनानी हैं। यदि एक विशेष अंक हमेशा तीसरे स्थान पर रहे तो कितनी संख्याएं बनेंगी?
(6)-digit numbers are to be formed from (6) distinct digits. If one particular digit always stays in the third position, how many numbers are possible?
Explanation opens after your attempt
A. (120)
Concept
The third position is fixed, so the remaining (5) digits are arranged in (5!) ways. The answer is (120).
Why this answer is correct
The correct answer is A. (120). The third position is fixed, so the remaining (5) digits are arranged in (5!) ways. The answer is (120).
Exam Tip
तीसरा स्थान निश्चित है, इसलिए शेष (5) अंक (5!) तरीकों से रखे जाएंगे। उत्तर (120) है।
Login to save your score, XP, coins and progress.
