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Mathematics Permutations MCQ Questions for Class 11 General

Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.

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Same chapter ke nearby topics ko revise jarur karein. Exam preparation ke liye yeh topics important hain. jisme niche ke ye 4 Topics hain.

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01 Practice Topic Combinations 600 MCQs 02 Practice Topic Derivations of formulas and their connections 600 MCQs 03 Practice Topic Factorial notation 590 MCQs 04 Practice Topic Fundamental principle of counting 574 MCQs

Permutations Practice Questions

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Question 1/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

यदि (5) अलग-अलग किताबों को एक पंक्ति में सजाना हो तो कितने तरीके होंगे?

If (5) different books are arranged in a row, how many ways are possible?

Explanation opens after your attempt
Correct Answer

A. (120)

Step 1

Concept

The arrangement of (5) distinct objects is (5!). In exams, use factorial for distinct objects.

Step 2

Why this answer is correct

The correct answer is A. (120). The arrangement of (5) distinct objects is (5!). In exams, use factorial for distinct objects.

Step 3

Exam Tip

(5) अलग वस्तुओं की व्यवस्था (5!) होती है। परीक्षा में अलग-अलग वस्तुओं के लिए factorial लगाएं।

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Question 2/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

(6) विद्यार्थियों में से (3) विद्यार्थियों को अध्यक्ष, सचिव और कोषाध्यक्ष के पदों पर कितने तरीकों से चुना जा सकता है?

In how many ways can (3) students be chosen from (6) students for the posts of president, secretary and treasurer?

Explanation opens after your attempt
Correct Answer

B. (120)

Step 1

Concept

Here the posts are different, so order matters and the answer is \({}^{6}P_{3}=120\). In exams, use permutation when posts are distinct.

Step 2

Why this answer is correct

The correct answer is B. (120). Here the posts are different, so order matters and the answer is \({}^{6}P_{3}=120\). In exams, use permutation when posts are distinct.

Step 3

Exam Tip

यहाँ पद अलग हैं इसलिए क्रम महत्त्वपूर्ण है और उत्तर \({}^{6}P_{3}=120\) है। परीक्षा में पद अलग हों तो permutation लें।

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Question 3/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

शब्द (CAT) के सभी अक्षरों से कितने अलग-अलग शब्द बनाए जा सकते हैं?

How many different words can be formed using all letters of the word (CAT)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

The word (CAT) has (3) distinct letters, so (3!=6) words are possible. For small words, arrange all letters using factorial.

Step 2

Why this answer is correct

The correct answer is C. (6). The word (CAT) has (3) distinct letters, so (3!=6) words are possible. For small words, arrange all letters using factorial.

Step 3

Exam Tip

(CAT) में (3) अलग अक्षर हैं इसलिए (3!=6) शब्द बनेंगे। छोटे शब्दों में सभी अक्षरों की व्यवस्था सीधे factorial से करें।

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Question 4/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

(4) अलग-अलग रंगों के झंडों को एक सीधी रेखा में कितने तरीकों से लगाया जा सकता है?

In how many ways can (4) different coloured flags be placed in a straight line?

Explanation opens after your attempt
Correct Answer

D. (24)

Step 1

Concept

The arrangement of (4) distinct flags is (4!=24). Placing in a straight line is a linear permutation.

Step 2

Why this answer is correct

The correct answer is D. (24). The arrangement of (4) distinct flags is (4!=24). Placing in a straight line is a linear permutation.

Step 3

Exam Tip

(4) अलग झंडों की व्यवस्था (4!=24) होती है। सीधी रेखा में लगाना linear permutation है।

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Question 5/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

\({}^{7}P_{2}\) का मान क्या है?

What is the value of \({}^{7}P_{2}\)?

Explanation opens after your attempt
Correct Answer

A. (42)

Step 1

Concept

\({}^{7}P_{2}=7\times6=42\). For small (r), multiply (r) decreasing factors.

Step 2

Why this answer is correct

The correct answer is A. (42). \({}^{7}P_{2}=7\times6=42\). For small (r), multiply (r) decreasing factors.

Step 3

Exam Tip

\({}^{7}P_{2}=7\times6=42\) होता है। छोटे (r) के लिए घटते हुए (r) गुणनखंड लें।

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Question 6/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

(8) खिलाड़ियों में से कप्तान और उपकप्तान कितने तरीकों से चुने जा सकते हैं?

In how many ways can a captain and vice-captain be chosen from (8) players?

Explanation opens after your attempt
Correct Answer

B. (56)

Step 1

Concept

Captain and vice-captain are distinct posts, so \({}^{8}P_{2}=56\). When roles differ, order matters.

Step 2

Why this answer is correct

The correct answer is B. (56). Captain and vice-captain are distinct posts, so \({}^{8}P_{2}=56\). When roles differ, order matters.

Step 3

Exam Tip

कप्तान और उपकप्तान अलग पद हैं इसलिए \({}^{8}P_{2}=56\) होगा। जब जिम्मेदारी अलग हो तो क्रम महत्त्वपूर्ण होता है।

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Question 7/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

अंकों (1,2,3) से बिना पुनरावृत्ति के कितनी (3)-अंकीय संख्याएँ बनेंगी?

How many (3)-digit numbers can be formed from digits (1,2,3) without repetition?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

The arrangement of three distinct digits is (3!=6). Without repetition, choices decrease place by place.

Step 2

Why this answer is correct

The correct answer is C. (6). The arrangement of three distinct digits is (3!=6). Without repetition, choices decrease place by place.

Step 3

Exam Tip

तीनों अलग अंकों की व्यवस्था (3!=6) है। बिना पुनरावृत्ति में हर स्थान के विकल्प घटते हैं।

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Question 8/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

(5) कुर्सियों पर (5) अलग-अलग लोगों को कितने तरीकों से बैठाया जा सकता है?

In how many ways can (5) different people be seated on (5) chairs?

Explanation opens after your attempt
Correct Answer

D. (120)

Step 1

Concept

The number of ways to seat (5) people in (5) places is (5!=120). Remember factorial for seating in a row.

Step 2

Why this answer is correct

The correct answer is D. (120). The number of ways to seat (5) people in (5) places is (5!=120). Remember factorial for seating in a row.

Step 3

Exam Tip

(5) लोगों को (5) स्थानों पर बैठाने के तरीके (5!=120) हैं। seating in a row में factorial याद रखें।

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Question 9/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

\({}^{5}P_{1}\) का मान क्या होगा?

What will be the value of \({}^{5}P_{1}\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

Since \({}^{n}P_{1}=n\), \({}^{5}P_{1}=5\). Choosing and arranging one object gives (n) ways.

Step 2

Why this answer is correct

The correct answer is A. (5). Since \({}^{n}P_{1}=n\), \({}^{5}P_{1}=5\). Choosing and arranging one object gives (n) ways.

Step 3

Exam Tip

\({}^{n}P_{1}=n\) होता है इसलिए \({}^{5}P_{1}=5\)। एक वस्तु चुनकर व्यवस्थित करने में (n) तरीके होते हैं।

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Question 10/600 Easy Mathematics Permutations and Combinations Permutations Class 11 Level 58

शब्द (DOG) के अक्षरों को कितने तरीकों से व्यवस्थित किया जा सकता है?

In how many ways can the letters of the word (DOG) be arranged?

Explanation opens after your attempt
Correct Answer

B. (6)

Step 1

Concept

The word (DOG) has (3) distinct letters, so there are (3!=6) arrangements. Use factorial when letters are distinct.

Step 2

Why this answer is correct

The correct answer is B. (6). The word (DOG) has (3) distinct letters, so there are (3!=6) arrangements. Use factorial when letters are distinct.

Step 3

Exam Tip

(DOG) में (3) अलग अक्षर हैं इसलिए (3!=6) व्यवस्थाएँ हैं। अक्षर अलग हों तो सीधे factorial प्रयोग करें।

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