असमानता \(\frac{x-4}{6}\le 2\) का हल क्या है?

What is the solution of the inequality \(\frac{x-4}{6}\le 2\)?

Explanation opens after your attempt
Correct Answer

A. \(x\le 16\)

Step 1

Concept

Multiplying both sides by (6) gives \(x-4\le 12\), so \(x\le 16\). Multiplying by a positive denominator keeps the sign unchanged.

Step 2

Why this answer is correct

The correct answer is A. \(x\le 16\). Multiplying both sides by (6) gives \(x-4\le 12\), so \(x\le 16\). Multiplying by a positive denominator keeps the sign unchanged.

Step 3

Exam Tip

दोनों पक्षों को (6) से गुणा करने पर \(x-4\le 12\), इसलिए \(x\le 16\)। धनात्मक हर से गुणा करने पर चिह्न वही रहता है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{x-4}{6}\le 2\) का हल क्या है? / What is the solution of the inequality \(\frac{x-4}{6}\le 2\)?

Correct Answer: A. \(x\le 16\). Explanation: दोनों पक्षों को (6) से गुणा करने पर \(x-4\le 12\), इसलिए \(x\le 16\)। धनात्मक हर से गुणा करने पर चिह्न वही रहता है। / Multiplying both sides by (6) gives \(x-4\le 12\), so \(x\le 16\). Multiplying by a positive denominator keeps the sign unchanged.

Which concept should I revise for this Mathematics MCQ?

Multiplying both sides by (6) gives \(x-4\le 12\), so \(x\le 16\). Multiplying by a positive denominator keeps the sign unchanged.

What exam hint can help solve this Mathematics question?

दोनों पक्षों को (6) से गुणा करने पर \(x-4\le 12\), इसलिए \(x\le 16\)। धनात्मक हर से गुणा करने पर चिह्न वही रहता है।