समीकरण \(\frac{1}{x^2}+x+1=0\) द्विघात समीकरण क्यों नहीं है?

Why is \(\frac{1}{x^2}+x+1=0\) not a quadratic equation?

Explanation opens after your attempt
Correct Answer

A. क्योंकि इसमें (x) की ऋणात्मक घात हैBecause it has a negative power of (x)

Step 1

Concept

\(\frac{1}{x^2}=x^{-2}\), which is not polynomial form. A quadratic equation cannot have a negative power of the variable.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि इसमें (x) की ऋणात्मक घात है / Because it has a negative power of (x). \(\frac{1}{x^2}=x^{-2}\), which is not polynomial form. A quadratic equation cannot have a negative power of the variable.

Step 3

Exam Tip

\(\frac{1}{x^2}=x^{-2}\) है जो बहुपद रूप नहीं है। द्विघात समीकरण में चर की ऋणात्मक घात नहीं होती।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(\frac{1}{x^2}+x+1=0\) द्विघात समीकरण क्यों नहीं है? / Why is \(\frac{1}{x^2}+x+1=0\) not a quadratic equation?

Correct Answer: A. क्योंकि इसमें (x) की ऋणात्मक घात है / Because it has a negative power of (x). Explanation: \(\frac{1}{x^2}=x^{-2}\) है जो बहुपद रूप नहीं है। द्विघात समीकरण में चर की ऋणात्मक घात नहीं होती। / \(\frac{1}{x^2}=x^{-2}\), which is not polynomial form. A quadratic equation cannot have a negative power of the variable.

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{x^2}=x^{-2}\), which is not polynomial form. A quadratic equation cannot have a negative power of the variable.

What exam hint can help solve this Mathematics question?

\(\frac{1}{x^2}=x^{-2}\) है जो बहुपद रूप नहीं है। द्विघात समीकरण में चर की ऋणात्मक घात नहीं होती।