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Class 10MathematicsReal NumbersIrrational numbersExpertLevel 15
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Which statement is correct about (\sqrt{2}\cdot \sqrt{3})?

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Answer and explanation

Correct answer: It is (\sqrt{6}) and irrational

Step 1: The product of radicals is (\sqrt{2}\cdot \sqrt{3}=\sqrt{6}). Step 2: Since (6) is not a perfect square (\sqrt{6}) is irrational. Step 3: In multiplication the numbers inside radicals multiply, not add.

Related tags

Radical MultiplicationIrrational NumbersClass 10

Frequently asked questions

What is the correct answer to this question?

It is (\sqrt{6}) and irrational

Why is this the correct answer?

Step 1: The product of radicals is (\sqrt{2}\cdot \sqrt{3}=\sqrt{6}). Step 2: Since (6) is not a perfect square (\sqrt{6}) is irrational. Step 3: In multiplication the numbers inside radicals multiply, not add.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Irrational numbers.

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10 more MCQs
  1. 1Which of the following numbers is irrational?
  2. 2Which of the following numbers is rational?
  3. 3What type of number is (\sqrt{16})?
  4. 4Which statement about (\sqrt{10}) is correct?
  5. 5Which of the following is an example of an irrational number?
  6. 6Which decimal form represents an irrational number?
  7. 7What type of number is (0.3333\ldots)?
  8. 8Which statement is correct about (0.101001000100001\ldots)?
  9. 9If (a) is a non-zero rational number and (b) is an irrational number, what type of number is (ab) generally?
  10. 10What type of number is (\sqrt{2}+3)?
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