Which option is a wrong step in the proof of irrationality of (\sqrt{2})?
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Answer and explanation
Correct answer: Directly assuming from (p^2=2q^2) that (q) is even
Step 1: From (p^2=2q^2), first (p^2) is even and hence (p) is even. Step 2: After writing (p=2k), we get (q^2=2k^2), so (q) is even. Step 3: Skipping this order makes the proof incomplete.
Frequently asked questions
What is the correct answer to this question?
Directly assuming from (p^2=2q^2) that (q) is even
Why is this the correct answer?
Step 1: From (p^2=2q^2), first (p^2) is even and hence (p) is even. Step 2: After writing (p=2k), we get (q^2=2k^2), so (q) is even. Step 3: Skipping this order makes the proof incomplete.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Irrational numbers.
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