Which of the following relations is always true for an arithmetic progression, where \(r\) is a positive integer and all indices are valid?
Answer and explanation
Correct answer: \(a_n=\frac{a_{n-r}+a_{n+r}}{2}\)
In an AP, \(a_k=a+(k-1)d\). Thus \(a_{n-r}=a_n-rd\) and \(a_{n+r}=a_n+rd\), so their average is \(a_n\). Exam tip: remember this for equally spaced terms.
Frequently asked questions
What is the correct answer to this question?
\(a_n=\frac{a_{n-r}+a_{n+r}}{2}\)
Why is this the correct answer?
In an AP, \(a_k=a+(k-1)d\). Thus \(a_{n-r}=a_n-rd\) and \(a_{n+r}=a_n+rd\), so their average is \(a_n\). Exam tip: remember this for equally spaced terms.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.