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Which middle step is correct while solving \(9x^2-30x+8=0\) by completing the square?
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Answer and explanation
Correct answer: \(\left(x-\frac{5}{3}\right)^2=\frac{17}{9}\)
First \(x^2-\frac{10}{3}x+\frac{8}{9}=0\) is obtained, then \(\left(x-\frac{5}{3}\right)^2=\frac{17}{9}\). In exams, divide by (a) first when \(a\neq1\).
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What is the correct answer to this question?
\(\left(x-\frac{5}{3}\right)^2=\frac{17}{9}\)
Why is this the correct answer?
First \(x^2-\frac{10}{3}x+\frac{8}{9}=0\) is obtained, then \(\left(x-\frac{5}{3}\right)^2=\frac{17}{9}\). In exams, divide by (a) first when \(a\neq1\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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