Which middle step is correct while solving \(3x^2-10x+3=0\) by completing the square?

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Answer and explanation

Correct answer: \(\left(x-\frac{5}{3}\right)^2=\frac{16}{9}\)

First we get \(x^2-\frac{10}{3}x+1=0\), then \(\left(x-\frac{5}{3}\right)^2=\frac{16}{9}\). In exams, divide by (a) first when \(a\neq1\).

What is the correct answer to this question?

\(\left(x-\frac{5}{3}\right)^2=\frac{16}{9}\)

Why is this the correct answer?

First we get \(x^2-\frac{10}{3}x+1=0\), then \(\left(x-\frac{5}{3}\right)^2=\frac{16}{9}\). In exams, divide by (a) first when \(a\neq1\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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