Which is the correct nth-term formula for an AP whose first term is 14 and each successive term is 3 less than the preceding term?

Question

Answer and explanation

Correct answer: $a_n=17-3n$

Here, $a=14$ and $d=-3$. Thus $a_n=a+(n-1)d=14-3(n-1)=17-3n$. In option B, putting $n=1$ gives 11, not 14. Exam tip: always verify the first term.

What is the correct answer to this question?

$a_n=17-3n$

Why is this the correct answer?

Here, $a=14$ and $d=-3$. Thus $a_n=a+(n-1)d=14-3(n-1)=17-3n$. In option B, putting $n=1$ gives 11, not 14. Exam tip: always verify the first term.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.