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Which formula correctly represents the sum of the first n terms of an arithmetic progression, where the first term is a and the common difference is d?

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Answer and explanation

Correct answer: \(S_n=\frac{n}{2}[2a+(n-1)d]\)

The sum of the first n AP terms is \(S_n=\frac{n}{2}[2a+(n-1)d]\). It also equals \(\frac{n}{2}(a+l)\), where \(l=a+(n-1)d\). Option B gives only the nth term. Exam tip: distinguish the sum formula from the nth-term formula.

Related tags

Arithmetic ProgressionApSum Of N TermsSequence FormulasClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

\(S_n=\frac{n}{2}[2a+(n-1)d]\)

Why is this the correct answer?

The sum of the first n AP terms is \(S_n=\frac{n}{2}[2a+(n-1)d]\). It also equals \(\frac{n}{2}(a+l)\), where \(l=a+(n-1)d\). Option B gives only the nth term. Exam tip: distinguish the sum formula from the nth-term formula.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.

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