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What will be the sum of the first (13) terms of the arithmetic progression (96,88,80,\ldots)?समांतर श्रेणी (96,88,80,\ldots) के पहले (13) पदों का योग कितना होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (624)(624)
The thirteenth term is (0), so (S_{13}=\frac{13}{2}(96+0)=624). In a decreasing progression, the last term can also be zero.तेरहवाँ पद (0) है, इसलिए (S_{13}=\frac{13}{2}(96+0)=624)। घटती श्रेणी में अंतिम पद शून्य भी हो सकता है।
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