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Subjects
Class 10MathematicsQuadratic EquationsMethods of Solving Quadratic EquationsHardLevel 34
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What will be the roots of (6x^2-7x-3=0) by factorisation method?

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Answer and explanation

Correct answer: (x=\frac{3}{2},-\frac{1}{3})

(6x^2-7x-3=(3x+1)(2x-3)), so the roots are (-\frac{1}{3}) and (\frac{3}{2}). In exams, solve both linear factors separately.

Related tags

QuadraticHardFactorisation

Frequently asked questions

What is the correct answer to this question?

(x=\frac{3}{2},-\frac{1}{3})

Why is this the correct answer?

(6x^2-7x-3=(3x+1)(2x-3)), so the roots are (-\frac{1}{3}) and (\frac{3}{2}). In exams, solve both linear factors separately.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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10 more MCQs
  1. 1Using factorisation method, what are the roots of (x^2-5x+6=0)?
  2. 2In factorisation method, how will (x^2+7x+12=0) be written?
  3. 3Which is the simplest method to solve (x^2-9=0)?
  4. 4If (x^2=16), what is the value of (x) by square root method?
  5. 5Using the zero-product rule, what are the solutions of x(x−4)=0?
  6. 6In completing square method for \(x^2+6x+5=0\), which number is added and subtracted?
  7. 7Which is the correct formula to find roots of (ax^2+bx+c=0) by quadratic formula?
  8. 8What do we get first after simplifying (2x^2-8=0)?
  9. 9What are the correct factors for (x^2-2x-8=0)?
  10. 10In which form can (x^2+4x+4=0) be written?
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