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What will be the roots of (14x^2-25x+6=0) by factorisation method?
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Answer and explanation
Correct answer: (x=\frac{3}{7},1)
(14x^2-25x+6=(7x-3)(2x-2)), so the roots are (\frac{3}{7}) and (1). In exams, also check by removing any common factor if present.
Frequently asked questions
What is the correct answer to this question?
(x=\frac{3}{7},1)
Why is this the correct answer?
(14x^2-25x+6=(7x-3)(2x-2)), so the roots are (\frac{3}{7}) and (1). In exams, also check by removing any common factor if present.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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