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What roots are obtained for (13x^2-52x+9=0) by completing square method?(13x^2-52x+9=0) के मूल पूर्ण वर्ग विधि से क्या होंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=2\pm\frac{\sqrt{559}}{13})(x=2\pm\frac{\sqrt{559}}{13})
Since ((x-2)^2=\frac{43}{13}), (x=2\pm\sqrt{\frac{43}{13}}=2\pm\frac{\sqrt{559}}{13}). In exams, rationalize the denominator.((x-2)^2=\frac{43}{13}), इसलिए (x=2\pm\sqrt{\frac{43}{13}}=2\pm\frac{\sqrt{559}}{13}) है। परीक्षा में हर को परिमेय बनाएं।
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