\(13x^2-52x+9=0\) के मूल पूर्ण वर्ग विधि से क्या होंगे?
What roots are obtained for \(13x^2-52x+9=0\) by completing square method?
Explanation opens after your attempt
Correct Answer
A. \(x=2\pm\frac{\sqrt{559}}{13}\)
Concept
Since ((x-2)2=\frac{43}{13}), \(x=2\pm\sqrt{\frac{43}{13}}=2\pm\frac{\sqrt{559}}{13}\). In exams, rationalize the denominator.
Why this answer is correct
The correct answer is A. \(x=2\pm\frac{\sqrt{559}}{13}\). Since ((x-2)2=\frac{43}{13}), \(x=2\pm\sqrt{\frac{43}{13}}=2\pm\frac{\sqrt{559}}{13}\). In exams, rationalize the denominator.
Exam Tip
((x-2)2=\frac{43}{13}), इसलिए \(x=2\pm\sqrt{\frac{43}{13}}=2\pm\frac{\sqrt{559}}{13}\) है। परीक्षा में हर को परिमेय बनाएं।
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