What is the sum of the first (18) terms of the arithmetic progression (1,6,11,\ldots)?
Answer and explanation
Correct answer: (783)
The governing concept is the sum formula for an arithmetic progression. The first term is a = 1 and the common difference is d = 6 − 1 = 5. The eighteenth term is a₁₈ = a + 17d = 1 + 17 × 5 = 86. Therefore, S₁₈ = n(a + l) ÷ 2 = 18(1 + 86) ÷ 2 = 9 × 87 = 783. Thus option B is correct. The factor 17 is used because the eighteenth term is reached through 18 − 1 intervals. The other choices usually result from using 18 differences, miscomputing the last term, or making an arithmetic error.
Frequently asked questions
What is the correct answer to this question?
(783)
Why is this the correct answer?
The governing concept is the sum formula for an arithmetic progression. The first term is a = 1 and the common difference is d = 6 − 1 = 5. The eighteenth term is a₁₈ = a + 17d = 1 + 17 × 5 = 86. Therefore, S₁₈ = n(a + l) ÷ 2 = 18(1 + 86) ÷ 2 = 9 × 87 = 783. Thus option B is correct. The factor 17 is used because the eighteenth term is reached through 18 − 1 intervals. The other choices usually result from using 18 differences, miscomputing the last term, or making an arithmetic error.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.
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