What is the sum of the first 12 terms of the arithmetic progression (5, 9, 13, 17, …)?
Answer and explanation
Correct answer: 324
The governing concept is the sum formula for the first n terms of an arithmetic progression: Sₙ = n/2[2a + (n − 1)d]. Here n = 12, a = 5, and d = 9 − 5 = 4. Therefore S₁₂ = 12/2[2(5) + 11(4)] = 6[10 + 44] = 6 × 54 = 324. Thus option B is correct. A common alternative check is to find the last term: a₁₂ = 5 + 11 × 4 = 49, then use S₁₂ = 12(5 + 49)/2 = 324. The other choices result from arithmetic errors in the bracket or from using the wrong number of intervals rather than the number of terms.
Frequently asked questions
What is the correct answer to this question?
324
Why is this the correct answer?
The governing concept is the sum formula for the first n terms of an arithmetic progression: Sₙ = n/2[2a + (n − 1)d]. Here n = 12, a = 5, and d = 9 − 5 = 4. Therefore S₁₂ = 12/2[2(5) + 11(4)] = 6[10 + 44] = 6 × 54 = 324. Thus option B is correct. A common alternative check is to find the last term: a₁₂ = 5 + 11 × 4 = 49, then use S₁₂ = 12(5 + 49)/2 = 324. The other choices result from arithmetic errors in the bracket or from using the wrong number of intervals rather than the number of terms.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.