समीकरण \(2x^2-7x+3=0\) के मूलों के व्युत्क्रमों का योग क्या है?

What is the sum of reciprocals of the roots of \(2x^2-7x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{7}{3}\)

Step 1

Concept

The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7}{3}\). The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\).

Step 3

Exam Tip

व्युत्क्रमों का योग \(\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहां \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\) है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(2x^2-7x+3=0\) के मूलों के व्युत्क्रमों का योग क्या है? / What is the sum of reciprocals of the roots of \(2x^2-7x+3=0\)?

Correct Answer: A. \(\frac{7}{3}\). Explanation: व्युत्क्रमों का योग \(\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहां \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\) है। / The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\).

Which concept should I revise for this Mathematics MCQ?

The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\).

What exam hint can help solve this Mathematics question?

व्युत्क्रमों का योग \(\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहां \(\frac{\frac{7}{2}}{\frac{3}{2}}=\frac{7}{3}\) है।