Muft Shiksha
Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHard
0 reads0 ratings0 helpful

What is the smallest number that leaves remainder (9) when divided by (28), (42), and (56)?

Answer and explanation

Correct answer: (177)

Step 1: Subtracting (9) makes the number divisible by (28), (42), and (56). Step 2: (28=2^2\times7), (42=2\times3\times7), and (56=2^3\times7), so LCM (=2^3\times3\times7=168). Hence the number is (168+9=177). Step 3: Add the common remainder at the end.

Related tags

Real-NumbersLcmRemainderHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq
सुधार सुझाएँ / Earn

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

KEEP PRACTISING

10 more MCQs
  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
  2. 2What is the HCF of (18) and (24) using prime factorisation?
  3. 3What is the LCM of (18) and (24) using prime factorisation?
  4. 4What is the HCF of (40) and (60)?
  5. 5What is the LCM of (40) and (60)?
  6. 6What will be the HCF of (45) and (75)?
  7. 7What will be the LCM of (45) and (75)?
  8. 8Which is the HCF of (32) and (48)?
  9. 9Which is the LCM of (32) and (48)?
  10. 10What is the HCF of (27) and (36)?
Found an issue? Help improve this questionMy reports and replies

Add Muft Shiksha to your Home Screen

In Safari, tap Share, then Add to Home Screen.