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What is the correct quadratic form of (\frac{x+1}{x}=\frac{6}{x+1}), (x\neq0,-1)?
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Answer and explanation
Correct answer: (x^2-4x+1=0)
From ((x+1)^2=6x), we get (x^2+2x+1-6x=0), that is (x^2-4x+1=0). In exams, avoid a wrong middle term.
Frequently asked questions
What is the correct answer to this question?
(x^2-4x+1=0)
Why is this the correct answer?
From ((x+1)^2=6x), we get (x^2+2x+1-6x=0), that is (x^2-4x+1=0). In exams, avoid a wrong middle term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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