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Class 10MathematicsQuadratic EquationsNature of RootsHard
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What is the correct condition for real roots of (5x^2-2(k+1)x+(k-3)=0)?

Answer and explanation

Correct answer: (k^2-3k+16\ge0)

Here (D=4[(k+1)^2-5(k-3)]=4(k^2-3k+16)). This expression is always positive, so real roots always exist.

Related tags

Quadratic EquationsAlways Real RootsParameterNature Of RootsMathematicsClass 10 Mcq
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