समीकरण \(x^2+2kx+9=0\) के वास्तविक मूल होने की शर्त कौन-सी है?
What is the condition for \(x^2+2kx+9=0\) to have real roots?
Explanation opens after your attempt
A. \(k\leq -3\) या \(k\geq 3\)\(k\leq -3\) or \(k\geq 3\)
Concept
For real roots, \(D\geq0\) is needed. Here \(4k^2-36\geq0\), so \(k\leq-3\) or \(k\geq3\).
Why this answer is correct
The correct answer is A. \(k\leq -3\) या \(k\geq 3\) / \(k\leq -3\) or \(k\geq 3\). For real roots, \(D\geq0\) is needed. Here \(4k^2-36\geq0\), so \(k\leq-3\) or \(k\geq3\).
Exam Tip
वास्तविक मूलों के लिए \(D\geq0\) चाहिए। यहाँ \(4k^2-36\geq0\), इसलिए \(k\leq-3\) या \(k\geq3\)।
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