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What is the common difference in the sequence (3a,3a-4,3a-8,\ldots)?

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Answer and explanation

Correct answer: -4

The common difference is found by subtracting a term from the term immediately after it. Here, \(d=(3a-4)-3a=-4\). Also, \((3a-8)-(3a-4)=-4\), confirming that the common difference is \(-4\). The number \(4\) is only the magnitude of the difference; for a decreasing AP, the common difference is negative. Exam tip: Write \(d=a_2-a_1\) and check the sign carefully.

Related tags

Arithmetic ProgressionCommon DifferenceAlgebraic SequenceNegative DifferenceClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

-4

Why is this the correct answer?

The common difference is found by subtracting a term from the term immediately after it. Here, \(d=(3a-4)-3a=-4\). Also, \((3a-8)-(3a-4)=-4\), confirming that the common difference is \(-4\). The number \(4\) is only the magnitude of the difference; for a decreasing AP, the common difference is negative. Exam tip: Write \(d=a_2-a_1\) and check the sign carefully.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Introduction to APs and common difference..

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