What is the (10)th term of the AP (25,31,37,43,\ldots)?
Answer and explanation
Correct answer: 79
In this AP, the first term is \(a=25\) and the common difference is \(d=31-25=6\). The \(n\)th term is given by \(a_n=a+(n-1)d\). Thus, \(a_{10}=25+(10-1)\times6=25+54=79\). Therefore, 79 is correct. The value 73 would result from adding only 8 common differences, but the 10th term is reached after 9 differences. Exam tip: always use \(n-1\), not \(n\), in the nth-term formula.
Frequently asked questions
What is the correct answer to this question?
79
Why is this the correct answer?
In this AP, the first term is \(a=25\) and the common difference is \(d=31-25=6\). The \(n\)th term is given by \(a_n=a+(n-1)d\). Thus, \(a_{10}=25+(10-1)\times6=25+54=79\). Therefore, 79 is correct. The value 73 would result from adding only 8 common differences, but the 10th term is reached after 9 differences. Exam tip: always use \(n-1\), not \(n\), in the nth-term formula.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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