What is the (10)th term of the AP (16,12,8,4,\ldots)?

Correct answer: \(-20\)

For this AP, the first term is \(a=16\) and the common difference is \(d=12-16=-4\). The \(n\)th term is given by \(a_n=a+(n-1)d\). Therefore, \(a_{10}=16+(10-1)(-4)=16-36=-20\). Hence, \(-20\) is correct. A value such as \(-18\) may result from an incorrect calculation or common difference. Exam tip: always use \(n-1\), not \(n\), in the nth-term formula.