What is the (10)th term in the AP (7,11,15,19,\ldots)?

Correct answer: \(43\)

The first term is \(a=7\), and the common difference is \(d=11-7=4\). The \(n\)th term is given by \(a_n=a+(n-1)d\). Therefore, \(a_{10}=7+(10-1)\times4=7+36=43\). Hence, \(43\) is correct. Choosing \(41\) would result from using an incorrect multiplier instead of counting the nine jumps from the first term. Exam tip: always use \((n-1)\) for the \(n\)th term of an AP.