What is (k) for equal roots of (x^2-2(k+5)x+k^2=0)?

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Correct answer: (k=-\frac{5}{2})

(D=4(k+5)^2-4k^2=0) gives ((k+5)^2=k^2), so (10k+25=0) and (k=-\frac{5}{2}). In exams, expand squares carefully.

What is the correct answer to this question?

(k=-\frac{5}{2})

Why is this the correct answer?

(D=4(k+5)^2-4k^2=0) gives ((k+5)^2=k^2), so (10k+25=0) and (k=-\frac{5}{2}). In exams, expand squares carefully.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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