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What is assumed at the beginning to prove that (\sqrt{5}) is irrational?(\sqrt{5}) को अपरिमेय सिद्ध करने की शुरुआत में क्या माना जाता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\sqrt{5}) is rational and (\sqrt{5}=\frac{p}{q}), where (p) and (q) are coprime(\sqrt{5}) परिमेय है और (\sqrt{5}=\frac{p}{q}), जहां (p) और (q) सहअभाज्य हैं
Step 1: In the contradiction method, we assume the opposite. Step 2: So (\sqrt{5}) is assumed rational and written as (\frac{p}{q}). Step 3: Do not forget to mention that (p) and (q) are coprime.चरण 1: विरोधाभास विधि में उलटी बात मानते हैं। चरण 2: इसलिए (\sqrt{5}) को परिमेय मानकर (\frac{p}{q}) के रूप में लिखा जाता है। चरण 3: (p) और (q) को सहअभाज्य लिखना न भूलें।
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