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What are the solutions of (\frac{x+4}{x}=\frac{25}{x+4}), (x\neq0,-4)?
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Answer and explanation
Correct answer: (x=1,16)
(x^2-17x+16=(x-1)(x-16)), so (x=1) and (x=16). In exams, check solutions against excluded denominator values.
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What is the correct answer to this question?
(x=1,16)
Why is this the correct answer?
(x^2-17x+16=(x-1)(x-16)), so (x=1) and (x=16). In exams, check solutions against excluded denominator values.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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