\(x^2+14x+10=0\) के मूल क्या हैं?

What are the roots of \(x^2+14x+10=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=-7\pm\sqrt{39}\)

Step 1

Concept

Since ((x+7)2=39), \(x=-7\pm\sqrt{39}\). In exams, write both values using \(\pm\).

Step 2

Why this answer is correct

The correct answer is A. \(x=-7\pm\sqrt{39}\). Since ((x+7)2=39), \(x=-7\pm\sqrt{39}\). In exams, write both values using \(\pm\).

Step 3

Exam Tip

((x+7)2=39), इसलिए \(x=-7\pm\sqrt{39}\) है। परीक्षा में \(\pm\) के दोनों मान लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+14x+10=0\) के मूल क्या हैं? / What are the roots of \(x^2+14x+10=0\)?

Correct Answer: A. \(x=-7\pm\sqrt{39}\). Explanation: ((x+7)2=39), इसलिए \(x=-7\pm\sqrt{39}\) है। परीक्षा में \(\pm\) के दोनों मान लिखें। / Since ((x+7)2=39), \(x=-7\pm\sqrt{39}\). In exams, write both values using \(\pm\).

Which concept should I revise for this Mathematics MCQ?

Since ((x+7)2=39), \(x=-7\pm\sqrt{39}\). In exams, write both values using \(\pm\).

What exam hint can help solve this Mathematics question?

((x+7)2=39), इसलिए \(x=-7\pm\sqrt{39}\) है। परीक्षा में \(\pm\) के दोनों मान लिखें।