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What are the roots of the quadratic equation \(5x^2-7x-6=0\)?

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Answer and explanation

Correct answer: \(x=2,\,-\frac{3}{5}\)

The quadratic factors as \(5x^2-7x-6=(5x+3)(x-2)\). Thus, \((5x+3)(x-2)=0\) gives \(x=-\frac{3}{5}\) or \(x=2\), so option A is correct. In option B, the signs of both roots are incorrect. Exam tip: when setting each factor equal to zero, remember to change the sign while solving for the root.

Related tags

Quadratic EquationsRootsFactorisation

Frequently asked questions

What is the correct answer to this question?

\(x=2,\,-\frac{3}{5}\)

Why is this the correct answer?

The quadratic factors as \(5x^2-7x-6=(5x+3)(x-2)\). Thus, \((5x+3)(x-2)=0\) gives \(x=-\frac{3}{5}\) or \(x=2\), so option A is correct. In option B, the signs of both roots are incorrect. Exam tip: when setting each factor equal to zero, remember to change the sign while solving for the root.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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