What are the roots of the equation \(2x^2-7x+5=0\)?
Answer and explanation
Correct answer: \(x=1,\frac{5}{2}\)
The factorisation is \(2x^2-7x+5=(2x-5)(x-1)\). Therefore, \((2x-5)(x-1)=0\) gives \(x=\frac{5}{2}\) or \(x=1\). The values in option D do not satisfy the original equation. As an exam tip, substitute the obtained roots back into the equation to verify them.
Frequently asked questions
What is the correct answer to this question?
\(x=1,\frac{5}{2}\)
Why is this the correct answer?
The factorisation is \(2x^2-7x+5=(2x-5)(x-1)\). Therefore, \((2x-5)(x-1)=0\) gives \(x=\frac{5}{2}\) or \(x=1\). The values in option D do not satisfy the original equation. As an exam tip, substitute the obtained roots back into the equation to verify them.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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