0 reads0 ratings0 helpful
What are the roots of (24x^2-50x+25=0)?
Advertisement
Answer and explanation
Correct answer: (x=\frac{5}{6},\frac{5}{4})
(24x^2-50x+25=(6x-5)(4x-5)), so the roots are (\frac{5}{6}) and (\frac{5}{4}). In exams, keep the denominator coefficients correctly.
Frequently asked questions
What is the correct answer to this question?
(x=\frac{5}{6},\frac{5}{4})
Why is this the correct answer?
(24x^2-50x+25=(6x-5)(4x-5)), so the roots are (\frac{5}{6}) and (\frac{5}{4}). In exams, keep the denominator coefficients correctly.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement