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What are the roots of (18x^2-27x+10=0)?
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Answer and explanation
Correct answer: (x=\frac{2}{3},\frac{5}{6})
(18x^2-27x+10=(3x-2)(6x-5)), so the roots are (\frac{2}{3}) and (\frac{5}{6}). In exams, write fractional roots in simplest form.
Frequently asked questions
What is the correct answer to this question?
(x=\frac{2}{3},\frac{5}{6})
Why is this the correct answer?
(18x^2-27x+10=(3x-2)(6x-5)), so the roots are (\frac{2}{3}) and (\frac{5}{6}). In exams, write fractional roots in simplest form.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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