Muft Shiksha
Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
Class 10MathematicsReal NumbersProof of irrationality of √2, √3, √5HardLevel 17

In the proof of (\sqrt{2}), (\frac{a}{b}) is in lowest form. If (a=2m) and (b=2n), which conclusion is most suitable?

Advertisement

Answer and explanation

Correct answer: (\frac{a}{b}) can be reduced to (\frac{m}{n})

Step 1: (a=2m) and (b=2n) show common factor (2) in numerator and denominator. Step 2: So (\frac{2m}{2n}=\frac{m}{n}). Step 3: This contradicts lowest form.

Tags

sqrt2 prooffraction reductionhardclass 10

Frequently asked questions

What is the correct answer to this question?

(\frac{a}{b}) can be reduced to (\frac{m}{n})

Why is this the correct answer?

Step 1: (a=2m) and (b=2n) show common factor (2) in numerator and denominator. Step 2: So (\frac{2m}{2n}=\frac{m}{n}). Step 3: This contradicts lowest form.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

Report question
Advertisement