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In an AP, a_8 = 52 and a_23 = 172. If a_(8r) = 292, what is r?एक समांतर श्रेणी में a_8 = 52 और a_23 = 172 हैं। यदि a_(8r) = 292, तो r का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 19/419/4
The common difference is d = (172 − 52)/(23 − 8) = 8. From a_n = 52 + (n − 8)8, setting a_n = 292 gives n = 38. Since the index is 8r, 8r = 38, so r = 19/4. Therefore, option B is correct.ಸಾರ್ವ अंतर d = (172 − 52)/(23 − 8) = 8 है। a_n = 52 + (n − 8)8 रखने पर a_n = 292 से n = 38 मिलता है। चूँकि पद का क्रमांक 8r है, इसलिए 8r = 38 और r = 19/4। अतः विकल्प B सही है।
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