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Class 10 Mathematics Arithmetic Progressions (AP)Finding the $n$th term of an APExpertLevel 66

In an AP (a_{20}=178) and (a_{52}=626). What is (a_{36})?

Answer and explanation

Correct answer: (402)

(a_{36}) is equally spaced between (a_{20}) and (a_{52}). Therefore (a_{36}=\frac{178+626}{2}=402).

Tags

ap expert middle term

Frequently asked questions

What is the correct answer to this question?

(402)

Why is this the correct answer?

(a_{36}) is equally spaced between (a_{20}) and (a_{52}). Therefore (a_{36}=\frac{178+626}{2}=402).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.

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