एक AP में \(a_{10}+a_{30}=500\) और \(a_{18}+a_{38}=820\) है। \(a_{58}\) क्या होगा?
In an AP \(a_{10}+a_{30}=500\) and \(a_{18}+a_{38}=820\). What is \(a_{58}\)?
Explanation opens after your attempt
Correct Answer
D. (1130)
Concept
The first sum gives (2a+38d=500) and the second gives (2a+54d=820). (d=20) and \(a_{58}=1130\).
Why this answer is correct
The correct answer is D. (1130). The first sum gives (2a+38d=500) and the second gives (2a+54d=820). (d=20) and \(a_{58}=1130\).
Exam Tip
पहले योग से (2a+38d=500) और दूसरे से (2a+54d=820)। (d=20) और \(a_{58}=1130\)।
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