यदि \(x=\sqrt{6}+\sqrt{2}\) और \(y=\sqrt{6}-\sqrt{2}\), तो \(\frac{x}{y}\) का सरल रूप क्या है?
If \(x=\sqrt{6}+\sqrt{2}\) and \(y=\sqrt{6}-\sqrt{2}\), what is the simplified form of \(\frac{x}{y}\)?
Explanation opens after your attempt
A. \(2+\sqrt{3}\)
Concept
\(\frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}-\sqrt{2}}\) में हर को संयुग्मी से परिमेय करें। / Rationalize the denominator of \(\frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}-\sqrt{2}}\).
Why this answer is correct
ऊपर (\(\sqrt{6}+\sqrt{2}\)2=8+4\sqrt{3}) और नीचे (6-2=4), इसलिए मान \(2+\sqrt{3}\) है। / The numerator becomes (\(\sqrt{6}+\sqrt{2}\)2=8+4\sqrt{3}), and the denominator is (6-2=4), so the value is \(2+\sqrt{3}\).
Exam Tip
भाग में संयुग्मी से गुणा करना प्रभावी तरीका है। / Multiplying by the conjugate is effective in such quotients.
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