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If \(x^2-6x+k\) is in the perfect-square form \((x-3)^2\), what is the value of \(k\)?
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Answer and explanation
Correct answer: 9
Expanding the perfect square gives \((x-3)^2=x^2-6x+9\). Comparing this with \(x^2-6x+k\), the constant term is \(k=9\). Therefore, option A is correct. Exam tip: in \((x-a)^2=x^2-2ax+a^2\), the constant term is \(a^2\).
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
Expanding the perfect square gives \((x-3)^2=x^2-6x+9\). Comparing this with \(x^2-6x+k\), the constant term is \(k=9\). Therefore, option A is correct. Exam tip: in \((x-a)^2=x^2-2ax+a^2\), the constant term is \(a^2\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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