If the roots of (x^2-23x+126=0) are (\alpha) and (\beta), what is (\alpha^2+\beta^2)?

Question

0 reads0 ratings0 helpful

Answer and explanation

Correct answer: (277)

(\alpha+\beta=23) and (\alpha\beta=126), so (\alpha^2+\beta^2=23^2-2(126)=277). In exams, remember ((\alpha+\beta)^2-2\alpha\beta).

What is the correct answer to this question?

(277)

Why is this the correct answer?

(\alpha+\beta=23) and (\alpha\beta=126), so (\alpha^2+\beta^2=23^2-2(126)=277). In exams, remember ((\alpha+\beta)^2-2\alpha\beta).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

Student feedback

No ratings yetWrite a review / Rate this question

Was this question useful?

👍 0 Helpful 👎 0 Not helpful

Difficulty

Easy0%

Medium0%

Hard0%

Was the explanation clear?

Yes 0% No 0%

0 responses

No published reviews yet.