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If the roots of (x^2-20x+91=0) are (\alpha) and (\beta), what is (\frac{1}{\alpha}+\frac{1}{\beta})?
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Answer and explanation
Correct answer: ( \frac{20}{91}) / (\frac{20}{91})
(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{20}{91}). In exams, first write sum and product in reciprocal questions.
Frequently asked questions
What is the correct answer to this question?
( \frac{20}{91}) / (\frac{20}{91})
Why is this the correct answer?
(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{20}{91}). In exams, first write sum and product in reciprocal questions.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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