If the roots of (x^2-19x+88=0) are (\alpha) and (\beta), what is (\alpha^2+\beta^2)?

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Answer and explanation

Correct answer: (185)

(\alpha+\beta=19) and (\alpha\beta=88), so (\alpha^2+\beta^2=19^2-2(88)=185). In exams, remember ((\alpha+\beta)^2-2\alpha\beta).

What is the correct answer to this question?

(185)

Why is this the correct answer?

(\alpha+\beta=19) and (\alpha\beta=88), so (\alpha^2+\beta^2=19^2-2(88)=185). In exams, remember ((\alpha+\beta)^2-2\alpha\beta).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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