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If the product of roots of (10x^2-23x+p=0) is (\frac{2}{5}), what is (p)?यदि (10x^2-23x+p=0) के मूलों का गुणनफल (\frac{2}{5}) है, तो (p) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (4)(4)
The product of roots is (\frac{p}{10}), so (\frac{p}{10}=\frac{2}{5}) gives (p=4). In exams, use the product formula (\frac{c}{a}).मूलों का गुणनफल (\frac{p}{10}) है, इसलिए (\frac{p}{10}=\frac{2}{5}) से (p=4) है। परीक्षा में गुणनफल का सूत्र (\frac{c}{a}) लगाएं।
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